-The displacement from the ground that the bullet must travel, s = 1.5m-The acceleration the bullet experiences. As gravity is accelerating the bullet downwards, a = g = ~9.81m/s^2-The initial velocity of the bullet vertically. As the bullet is stationary vertically (it is only travelling horizontally at the start), u = 0m
If the ball is kicked with an initial velocity of 25.0 m/s at an angle of 60.0 o above the ground, what is the "hang time"? The initial vertical component of the velocity is. The hang-time is found by setting y = 0 in one of the equations for the vertical displacement. Problem 3-28. A horizontal rifle is fired at a bull's-eye.
A bullet is fired horizontally at a height of 1.3 meters at a velocity of 950 m/s. Assume no air resistance. ... A cannonball is fired at a 45.0° angle and an initial velocity of 625 m/s. Assume no air resistance. ... A stone is thrown off a bridge 70 meters above the water at an angle of elevations of 48 \degree ° with an initial velocity of ...
Now we must find v 0y, the component of the initial velocity in the y-direction. It is given by v 0y = v 0 sin θ, where v 0y is the initial velocity of 70.0 m/s, and θ 0 = 75.0º is the initial angle. Thus, v Oy = v 0 sin θ 0 = (70.0 m/s)(sin 75º) = 67.6 m/s. and y is
2. A person standing on top of a 30.0 m high building throws a ball with an initial velocity of 20. m/s at an angle of 20.0° below horizontal. How far from the base of the building will the ball land? 3. An arrow is fired downward at an angle of 45 degrees from the top of a 200 m cliff with a velocity of 60.0 m/s. a.
What is the velocity of the sailboat relative to the woman and what angle of travel does the sailboat make with respect to her? (Answer: 13.45 km/h, 48.01 degrees or 41.99 degrees) Problem # 5 If a sprinter runs 100 m in 10 seconds, what is his average velocity? (Answer: 10 m/s) Problem # 6 The world record for the men's marathon is 2:03:38.
Bullets were fired at different angles of incidence and the position of point R was recorded in addi-tion to observations on penetration in deal board. The angle of ricochet (r) was calculated with the help of the simple relation OR.' Zr = tan,-I0 The angle of incidence was increased in steps of 150 starting from 15'.